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comingsoon
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Posted on 04-26-12 2:19
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Geshe
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Posted on 04-26-12 3:21
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So it basically sum of volume of 10 trapezoid prism.
So,
area of a floor y = area of the ceiling of the floor x, where y=x+1
So, basically we can find the vloume of 10 different trapezoid prism and sum them up.
V= (1/2)*(Area of the floor + area of its celing) * (height of the room)
V=(15/2)*(Area of the floor+Area of the celing) [Notice that height of the room is the same for each floor=15 units)
Total Volume= sum of all Vs.
for instance,
V1= (25+23)* (15) cubic units
=360 unit^3.
So your total volume should be 2190 cubic units.
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comingsoon
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Posted on 04-26-12 3:59
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Thanks much, is there anyway we can solve this problem via intragal method?
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Sparty
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Posted on 04-26-12 4:06
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The volume of each floor is calculated as
Where l represents the lenght of the floor, w is for the width and h is the height.
You have the area of each floor, and also the height.
The area of the floor is caculated as
So if you use this equation in the first I gave to you, one can obtain this:
The volume for each floor is then calculated with the data you gave in the problem.
For example, for the first floor you have Area=25 ft. and Height=15 ft.
The volume of the first floor is then V=A*h=(25 ft.)*(15 ft.)=375 square feet
Calculating for the rest of the floors:
Floor number
|
Area (ft.)
|
Height (ft.)
|
Volume (sq ft.)
|
Ground
|
25
|
15
|
375
|
2
|
23
|
15
|
345
|
3
|
20
|
15
|
300
|
4
|
18
|
15
|
270
|
5
|
16
|
15
|
240
|
6
|
14
|
15
|
210
|
7
|
12
|
15
|
180
|
8 |
10 |
15 |
150 |
9 |
9 |
15 |
135 |
10 |
8 |
15 |
120 |
Roof |
7 |
15 |
105 |
Then you calculate the total volume of the building, summing the volume column of the table.
The total volume of the building is 2430 square feet.
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Geshe
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Posted on 04-26-12 4:25
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This could be Reimann sum which is part of calculus 1. Are you taking Calc 3?
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Geshe
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Posted on 04-26-12 4:33
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this there is no function given nor we have any addition information igven, we need to do reimann sum.
I think taking volume of trapeziod prism will be better than taking cuboids.
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comingsoon
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Posted on 04-26-12 4:53
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yas this is cal II problem?
that will be great if you show me process of Reimann sum.
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Geshe
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Posted on 04-26-12 5:09
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hint;
here
delta x= delta height = 15/2
anf f(x) =(1/2) of ( bottom area+ top area)
Last edited: 26-Apr-12 05:09 PM
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comingsoon
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Posted on 05-03-12 9:55
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@geshe BIG thanks for your help. I wanna share my happiness with you that I got 99 on that 'home exam' paper. Thanks.
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Geshe
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Posted on 05-03-12 11:17
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Wow 99 is a really good grade!!!! Congratulation!!! I am really happy for you
Last edited: 03-May-12 11:18 PM
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